9b2=324

Solution for 9b2=324 equation:

9b^2=324

We move all terms to the left:

9b^2-(324)=0

a = 9; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·9·(-324)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*9}=\frac{-108}{18}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*9}=\frac{108}{18}
=6
$