9b=63/b=

Solution for 9b=63/b= equation:

9b=63/b=

We move all terms to the left:

9b-(63/b)=0


Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

9b-(+63/b)=0

We get rid of parentheses

9b-63/b=0

We multiply all the terms by the denominator


9b*b-63=0

Wy multiply elements

9b^2-63=0

a = 9; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·9·(-63)
Δ = 2268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2268}=\sqrt{324*7}=\sqrt{324}*\sqrt{7}=18\sqrt{7}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{7}}{2*9}=\frac{0-18\sqrt{7}}{18}
=-\frac{18\sqrt{7}}{18}
=-\sqrt{7}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{7}}{2*9}=\frac{0+18\sqrt{7}}{18}
=\frac{18\sqrt{7}}{18}
=\sqrt{7}
$