9c+16c-16=3(9c-18)

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Solution for 9c+16c-16=3(9c-18) equation: 



9c+16c-16=3(9c-18)

We move all terms to the left:

9c+16c-16-(3(9c-18))=0

We add all the numbers together, and all the variables

25c-(3(9c-18))-16=0



We calculate terms in parentheses: -(3(9c-18)), so:

3(9c-18)

We multiply parentheses

27c-54

Back to the equation:

-(27c-54)



We get rid of parentheses

25c-27c+54-16=0

We add all the numbers together, and all the variables

-2c+38=0

We move all terms containing c to the left, all other terms to the right

-2c=-38

c=-38/-2

c=+19

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