9c+4-5c=2(c-3)

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Solution for 9c+4-5c=2(c-3) equation: 



9c+4-5c=2(c-3)

We move all terms to the left:

9c+4-5c-(2(c-3))=0

We add all the numbers together, and all the variables

4c-(2(c-3))+4=0



We calculate terms in parentheses: -(2(c-3)), so:

2(c-3)

We multiply parentheses

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

4c-2c+6+4=0

We add all the numbers together, and all the variables

2c+10=0

We move all terms containing c to the left, all other terms to the right

2c=-10

c=-10/2

c=-5

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