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9c=6+5(c+2)
We move all terms to the left:
9c-(6+5(c+2))=0
We calculate terms in parentheses: -(6+5(c+2)), so:We get rid of parentheses
6+5(c+2)
determiningTheFunctionDomain 5(c+2)+6
We multiply parentheses
5c+10+6
We add all the numbers together, and all the variables
5c+16
Back to the equation:
-(5c+16)
9c-5c-16=0
We add all the numbers together, and all the variables
4c-16=0
We move all terms containing c to the left, all other terms to the right
4c=16
c=16/4
c=4
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