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9*cos((1/6)*x) = 0
cos((1/6)*x) = 0
cos((1/6)*x) = 0 <=> (1/6)*x = pi*k_1+pi/2 i k_1 należy do I
t_1 = pi*k_1+pi/2
(1/6)*x-t_1 = 0
1/6*x-t_1 = 0 // + t_1
1/6*x = t_1 // : 1/6
x = t_1/1/6
x = 6*t_1
x = 6*pi*k_1+pi/2 i k_1 należy do I
9*cos((1/6)*x) = 0 <=> 9 = 0 or 9*cos((1/6)*x) = 0 <=> cos((1/6)*x) = 0
x = 6*pi*k_1+pi/2
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