9d(5d+3)=0

Solution for 9d(5d+3)=0 equation:

9d(5d+3)=0

We multiply parentheses

45d^2+27d=0

a = 45; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·45·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*45}=\frac{-54}{90}
=-3/5
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*45}=\frac{0}{90}
=0
$