9f-12+28=2f=2f+15-10f-29

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Solution for 9f-12+28=2f=2f+15-10f-29 equation:



9f-12+28=2f=2f+15-10f-29
We move all terms to the left:
9f-12+28-(2f)=0
We add all the numbers together, and all the variables
7f+16=0
We move all terms containing f to the left, all other terms to the right
7f=-16
f=-16/7
f=-2+2/7

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