9k+11(-8k+1)=4(3-3k)-1

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Solution for 9k+11(-8k+1)=4(3-3k)-1 equation: 



9k+11(-8k+1)=4(3-3k)-1

We move all terms to the left:

9k+11(-8k+1)-(4(3-3k)-1)=0

We add all the numbers together, and all the variables

9k+11(-8k+1)-(4(-3k+3)-1)=0

We multiply parentheses

9k-88k-(4(-3k+3)-1)+11=0



We calculate terms in parentheses: -(4(-3k+3)-1), so:

4(-3k+3)-1

We multiply parentheses

-12k+12-1

We add all the numbers together, and all the variables

-12k+11

Back to the equation:

-(-12k+11)



We add all the numbers together, and all the variables

-79k-(-12k+11)+11=0

We get rid of parentheses

-79k+12k-11+11=0

We add all the numbers together, and all the variables

-67k=0

k=0/-67

k=0

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