9k-10=2+5(k+5)

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Solution for 9k-10=2+5(k+5) equation: 



9k-10=2+5(k+5)

We move all terms to the left:

9k-10-(2+5(k+5))=0



We calculate terms in parentheses: -(2+5(k+5)), so:

2+5(k+5)

determiningTheFunctionDomain
5(k+5)+2

We multiply parentheses

5k+25+2

We add all the numbers together, and all the variables

5k+27

Back to the equation:

-(5k+27)



We get rid of parentheses

9k-5k-27-10=0

We add all the numbers together, and all the variables

4k-37=0

We move all terms containing k to the left, all other terms to the right

4k=37

k=37/4

k=9+1/4

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