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9k^2-49=0
a = 9; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·9·(-49)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*9}=\frac{-42}{18} =-2+1/3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*9}=\frac{42}{18} =2+1/3 $
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