9k=3(k-5)-3

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Solution for 9k=3(k-5)-3 equation: 



9k=3(k-5)-3

We move all terms to the left:

9k-(3(k-5)-3)=0



We calculate terms in parentheses: -(3(k-5)-3), so:

3(k-5)-3

We multiply parentheses

3k-15-3

We add all the numbers together, and all the variables

3k-18

Back to the equation:

-(3k-18)



We get rid of parentheses

9k-3k+18=0

We add all the numbers together, and all the variables

6k+18=0

We move all terms containing k to the left, all other terms to the right

6k=-18

k=-18/6

k=-3

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