9m-21=3(m-7)+6m

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Solution for 9m-21=3(m-7)+6m equation: 



9m-21=3(m-7)+6m

We move all terms to the left:

9m-21-(3(m-7)+6m)=0



We calculate terms in parentheses: -(3(m-7)+6m), so:

3(m-7)+6m

We add all the numbers together, and all the variables

6m+3(m-7)

We multiply parentheses

6m+3m-21

We add all the numbers together, and all the variables

9m-21

Back to the equation:

-(9m-21)



We get rid of parentheses

9m-9m+21-21=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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