9m-3(m+6)=2m(m+1)

Solution for 9m-3(m+6)=2m(m+1) equation:

9m-3(m+6)=2m(m+1)

We move all terms to the left:

9m-3(m+6)-(2m(m+1))=0

We multiply parentheses

9m-3m-(2m(m+1))-18=0


We calculate terms in parentheses: -(2m(m+1)), so:

2m(m+1)

We multiply parentheses

2m^2+2m

Back to the equation:

-(2m^2+2m)


We add all the numbers together, and all the variables

6m-(2m^2+2m)-18=0

We get rid of parentheses

-2m^2+6m-2m-18=0

We add all the numbers together, and all the variables

-2m^2+4m-18=0

a = -2; b = 4; c = -18;
Δ = b2-4ac
Δ = 42-4·(-2)·(-18)
Δ = -128
Delta is less than zero, so there is no solution for the equation