9m2+81m+72=0

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Solution for 9m2+81m+72=0 equation:



9m^2+81m+72=0
a = 9; b = 81; c = +72;
Δ = b2-4ac
Δ = 812-4·9·72
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-63}{2*9}=\frac{-144}{18} =-8 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+63}{2*9}=\frac{-18}{18} =-1 $

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