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9m^2-15m-1116=0
a = 9; b = -15; c = -1116;
Δ = b2-4ac
Δ = -152-4·9·(-1116)
Δ = 40401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40401}=201$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-201}{2*9}=\frac{-186}{18} =-10+1/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+201}{2*9}=\frac{216}{18} =12 $
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