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9m^2-15m-1160=0
a = 9; b = -15; c = -1160;
Δ = b2-4ac
Δ = -152-4·9·(-1160)
Δ = 41985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{41985}=\sqrt{9*4665}=\sqrt{9}*\sqrt{4665}=3\sqrt{4665}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3\sqrt{4665}}{2*9}=\frac{15-3\sqrt{4665}}{18} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3\sqrt{4665}}{2*9}=\frac{15+3\sqrt{4665}}{18} $
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