9n+32=7n-2n(n-2)

Solution for 9n+32=7n-2n(n-2) equation:

9n+32=7n-2n(n-2)

We move all terms to the left:

9n+32-(7n-2n(n-2))=0


We calculate terms in parentheses: -(7n-2n(n-2)), so:

7n-2n(n-2)

We multiply parentheses

-2n^2+7n+4n

We add all the numbers together, and all the variables

-2n^2+11n

Back to the equation:

-(-2n^2+11n)


We get rid of parentheses

2n^2-11n+9n+32=0

We add all the numbers together, and all the variables

2n^2-2n+32=0

a = 2; b = -2; c = +32;
Δ = b2-4ac
Δ = -22-4·2·32
Δ = -252
Delta is less than zero, so there is no solution for the equation