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9n+4=3n^2-0.75
We move all terms to the left:
9n+4-(3n^2-0.75)=0
We get rid of parentheses
-3n^2+9n+0.75+4=0
We add all the numbers together, and all the variables
-3n^2+9n+4.75=0
a = -3; b = 9; c = +4.75;
Δ = b2-4ac
Δ = 92-4·(-3)·4.75
Δ = 138
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{138}}{2*-3}=\frac{-9-\sqrt{138}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{138}}{2*-3}=\frac{-9+\sqrt{138}}{-6} $
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