9n+68=2(2n-2)

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Solution for 9n+68=2(2n-2) equation:



9n+68=2(2n-2)
We move all terms to the left:
9n+68-(2(2n-2))=0
We calculate terms in parentheses: -(2(2n-2)), so:
2(2n-2)
We multiply parentheses
4n-4
Back to the equation:
-(4n-4)
We get rid of parentheses
9n-4n+4+68=0
We add all the numbers together, and all the variables
5n+72=0
We move all terms containing n to the left, all other terms to the right
5n=-72
n=-72/5
n=-14+2/5

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