9n+68=2(2n-2)

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Solution for 9n+68=2(2n-2) equation: 



9n+68=2(2n-2)

We move all terms to the left:

9n+68-(2(2n-2))=0



We calculate terms in parentheses: -(2(2n-2)), so:

2(2n-2)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We get rid of parentheses

9n-4n+4+68=0

We add all the numbers together, and all the variables

5n+72=0

We move all terms containing n to the left, all other terms to the right

5n=-72

n=-72/5

n=-14+2/5

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