9n-3(6-5n)=n-2(3n+9)

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Solution for 9n-3(6-5n)=n-2(3n+9) equation: 



9n-3(6-5n)=n-2(3n+9)

We move all terms to the left:

9n-3(6-5n)-(n-2(3n+9))=0

We add all the numbers together, and all the variables

9n-3(-5n+6)-(n-2(3n+9))=0

We multiply parentheses

9n+15n-(n-2(3n+9))-18=0



We calculate terms in parentheses: -(n-2(3n+9)), so:

n-2(3n+9)

We multiply parentheses

n-6n-18

We add all the numbers together, and all the variables

-5n-18

Back to the equation:

-(-5n-18)



We add all the numbers together, and all the variables

24n-(-5n-18)-18=0

We get rid of parentheses

24n+5n+18-18=0

We add all the numbers together, and all the variables

29n=0

n=0/29

n=0

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