9n-3=12+3(n+2)

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Solution for 9n-3=12+3(n+2) equation: 



9n-3=12+3(n+2)

We move all terms to the left:

9n-3-(12+3(n+2))=0



We calculate terms in parentheses: -(12+3(n+2)), so:

12+3(n+2)

determiningTheFunctionDomain
3(n+2)+12

We multiply parentheses

3n+6+12

We add all the numbers together, and all the variables

3n+18

Back to the equation:

-(3n+18)



We get rid of parentheses

9n-3n-18-3=0

We add all the numbers together, and all the variables

6n-21=0

We move all terms containing n to the left, all other terms to the right

6n=21

n=21/6

n=3+1/2

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