9n-3=7(n+3)=2n

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Solution for 9n-3=7(n+3)=2n equation: 



9n-3=7(n+3)=2n

We move all terms to the left:

9n-3-(7(n+3))=0



We calculate terms in parentheses: -(7(n+3)), so:

7(n+3)

We multiply parentheses

7n+21

Back to the equation:

-(7n+21)



We get rid of parentheses

9n-7n-21-3=0

We add all the numbers together, and all the variables

2n-24=0

We move all terms containing n to the left, all other terms to the right

2n=24

n=24/2

n=12

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