9n2+3n-5700=0

Solution for 9n2+3n-5700=0 equation:

9n^2+3n-5700=0

a = 9; b = 3; c = -5700;
Δ = b2-4ac
Δ = 32-4·9·(-5700)
Δ = 205209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{205209}=453$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-453}{2*9}=\frac{-456}{18}
=-25+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+453}{2*9}=\frac{450}{18}
=25
$