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9n^2-18n-27=0
a = 9; b = -18; c = -27;
Δ = b2-4ac
Δ = -182-4·9·(-27)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-36}{2*9}=\frac{-18}{18} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+36}{2*9}=\frac{54}{18} =3 $
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