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9n^2=9
We move all terms to the left:
9n^2-(9)=0
a = 9; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·9·(-9)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*9}=\frac{-18}{18} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*9}=\frac{18}{18} =1 $
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