9p(p-4)=-18

Solution for 9p(p-4)=-18 equation:

9p(p-4)=-18

We move all terms to the left:

9p(p-4)-(-18)=0

We add all the numbers together, and all the variables

9p(p-4)+18=0

We multiply parentheses

9p^2-36p+18=0

a = 9; b = -36; c = +18;
Δ = b2-4ac
Δ = -362-4·9·18
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-18\sqrt{2}}{2*9}=\frac{36-18\sqrt{2}}{18}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+18\sqrt{2}}{2*9}=\frac{36+18\sqrt{2}}{18}
$