9q(8q+7)=0

Solution for 9q(8q+7)=0 equation:

9q(8q+7)=0

We multiply parentheses

72q^2+63q=0

a = 72; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·72·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*72}=\frac{-126}{144}
=-7/8
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*72}=\frac{0}{144}
=0
$