9q+(1-q)=1q+7(1-q)

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Solution for 9q+(1-q)=1q+7(1-q) equation:



9q+(1-q)=1q+7(1-q)
We move all terms to the left:
9q+(1-q)-(1q+7(1-q))=0
We add all the numbers together, and all the variables
9q+(-1q+1)-(1q+7(-1q+1))=0
We get rid of parentheses
9q-1q-(1q+7(-1q+1))+1=0
We calculate terms in parentheses: -(1q+7(-1q+1)), so:
1q+7(-1q+1)
We add all the numbers together, and all the variables
q+7(-1q+1)
We multiply parentheses
q-7q+7
We add all the numbers together, and all the variables
-6q+7
Back to the equation:
-(-6q+7)
We add all the numbers together, and all the variables
8q-(-6q+7)+1=0
We get rid of parentheses
8q+6q-7+1=0
We add all the numbers together, and all the variables
14q-6=0
We move all terms containing q to the left, all other terms to the right
14q=6
q=6/14
q=3/7

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