9q-(5q+16)=3-(4q-2)

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Solution for 9q-(5q+16)=3-(4q-2) equation: 



9q-(5q+16)=3-(4q-2)

We move all terms to the left:

9q-(5q+16)-(3-(4q-2))=0

We get rid of parentheses

9q-5q-(3-(4q-2))-16=0



We calculate terms in parentheses: -(3-(4q-2)), so:

3-(4q-2)

determiningTheFunctionDomain
-(4q-2)+3

We get rid of parentheses

-4q+2+3

We add all the numbers together, and all the variables

-4q+5

Back to the equation:

-(-4q+5)



We add all the numbers together, and all the variables

4q-(-4q+5)-16=0

We get rid of parentheses

4q+4q-5-16=0

We add all the numbers together, and all the variables

8q-21=0

We move all terms containing q to the left, all other terms to the right

8q=21

q=21/8

q=2+5/8

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