9q2+24q+16=0

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Solution for 9q2+24q+16=0 equation: 



9q^2+24q+16=0

a = 9; b = 24; c = +16;
Δ = b2-4ac
Δ = 242-4·9·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-24}{18}=-1+1/3$

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