9r+2=(7(r-5))/3

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Solution for 9r+2=(7(r-5))/3 equation: 



9r+2=(7(r-5))/3

We move all terms to the left:

9r+2-((7(r-5))/3)=0

We multiply all the terms by the denominator


9r*3)-((7(r-5))+2*3)=0

We add all the numbers together, and all the variables

9r*3)-((7(r-5))=0

Wy multiply elements

27r^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{54}=0$

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