9r-3(r+4)=5(2r-4)-8

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Solution for 9r-3(r+4)=5(2r-4)-8 equation: 



9r-3(r+4)=5(2r-4)-8

We move all terms to the left:

9r-3(r+4)-(5(2r-4)-8)=0

We multiply parentheses

9r-3r-(5(2r-4)-8)-12=0



We calculate terms in parentheses: -(5(2r-4)-8), so:

5(2r-4)-8

We multiply parentheses

10r-20-8

We add all the numbers together, and all the variables

10r-28

Back to the equation:

-(10r-28)



We add all the numbers together, and all the variables

6r-(10r-28)-12=0

We get rid of parentheses

6r-10r+28-12=0

We add all the numbers together, and all the variables

-4r+16=0

We move all terms containing r to the left, all other terms to the right

-4r=-16

r=-16/-4

r=+4

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