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9r-5/4r-8=6
We move all terms to the left:
9r-5/4r-8-(6)=0
Domain of the equation: 4r!=0We add all the numbers together, and all the variables
r!=0/4
r!=0
r∈R
9r-5/4r-14=0
We multiply all the terms by the denominator
9r*4r-14*4r-5=0
Wy multiply elements
36r^2-56r-5=0
a = 36; b = -56; c = -5;
Δ = b2-4ac
Δ = -562-4·36·(-5)
Δ = 3856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3856}=\sqrt{16*241}=\sqrt{16}*\sqrt{241}=4\sqrt{241}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{241}}{2*36}=\frac{56-4\sqrt{241}}{72} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{241}}{2*36}=\frac{56+4\sqrt{241}}{72} $
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