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9r^2+18r-27=0
a = 9; b = 18; c = -27;
Δ = b2-4ac
Δ = 182-4·9·(-27)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-36}{2*9}=\frac{-54}{18} =-3 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+36}{2*9}=\frac{18}{18} =1 $
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