9r2+18r-27=0

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Solution for 9r2+18r-27=0 equation:



9r^2+18r-27=0
a = 9; b = 18; c = -27;
Δ = b2-4ac
Δ = 182-4·9·(-27)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-36}{2*9}=\frac{-54}{18} =-3 $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+36}{2*9}=\frac{18}{18} =1 $

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