9s2+s-1=0

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Solution for 9s2+s-1=0 equation: 



9s^2+s-1=0

a = 9; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·9·(-1)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{37}}{2*9}=\frac{-1-\sqrt{37}}{18}
$


$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{37}}{2*9}=\frac{-1+\sqrt{37}}{18}
$

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