9t+36=6+3(1+t)

Solution for 9t+36=6+3(1+t) equation:

9t+36=6+3(1+t)

We move all terms to the left:

9t+36-(6+3(1+t))=0

We add all the numbers together, and all the variables

9t-(6+3(t+1))+36=0


We calculate terms in parentheses: -(6+3(t+1)), so:

6+3(t+1)

determiningTheFunctionDomain
3(t+1)+6

We multiply parentheses

3t+3+6

We add all the numbers together, and all the variables

3t+9

Back to the equation:

-(3t+9)


We get rid of parentheses

9t-3t-9+36=0

We add all the numbers together, and all the variables

6t+27=0

We move all terms containing t to the left, all other terms to the right

6t=-27

t=-27/6

t=-4+1/2