9t+36=6+3(1+t)

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Solution for 9t+36=6+3(1+t) equation:



9t+36=6+3(1+t)
We move all terms to the left:
9t+36-(6+3(1+t))=0
We add all the numbers together, and all the variables
9t-(6+3(t+1))+36=0
We calculate terms in parentheses: -(6+3(t+1)), so:
6+3(t+1)
determiningTheFunctionDomain 3(t+1)+6
We multiply parentheses
3t+3+6
We add all the numbers together, and all the variables
3t+9
Back to the equation:
-(3t+9)
We get rid of parentheses
9t-3t-9+36=0
We add all the numbers together, and all the variables
6t+27=0
We move all terms containing t to the left, all other terms to the right
6t=-27
t=-27/6
t=-4+1/2

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