9t-2*(2t+3)=t-6

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Solution for 9t-2*(2t+3)=t-6 equation: 



9t-2(2t+3)=t-6

We move all terms to the left:

9t-2(2t+3)-(t-6)=0

We multiply parentheses

9t-4t-(t-6)-6=0

We get rid of parentheses

9t-4t-t+6-6=0

We add all the numbers together, and all the variables

4t=0

t=0/4

t=0

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