9t2+5t-1=0

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Solution for 9t2+5t-1=0 equation:



9t^2+5t-1=0
a = 9; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·9·(-1)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{61}}{2*9}=\frac{-5-\sqrt{61}}{18} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{61}}{2*9}=\frac{-5+\sqrt{61}}{18} $

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