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9t^2-17t-2=0
a = 9; b = -17; c = -2;
Δ = b2-4ac
Δ = -172-4·9·(-2)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-19}{2*9}=\frac{-2}{18} =-1/9 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+19}{2*9}=\frac{36}{18} =2 $
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