9u+22=2(u-3)

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Solution for 9u+22=2(u-3) equation: 



9u+22=2(u-3)

We move all terms to the left:

9u+22-(2(u-3))=0



We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)



We get rid of parentheses

9u-2u+6+22=0

We add all the numbers together, and all the variables

7u+28=0

We move all terms containing u to the left, all other terms to the right

7u=-28

u=-28/7

u=-4

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