9u+33=3(u-5)

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Solution for 9u+33=3(u-5) equation: 



9u+33=3(u-5)

We move all terms to the left:

9u+33-(3(u-5))=0



We calculate terms in parentheses: -(3(u-5)), so:

3(u-5)

We multiply parentheses

3u-15

Back to the equation:

-(3u-15)



We get rid of parentheses

9u-3u+15+33=0

We add all the numbers together, and all the variables

6u+48=0

We move all terms containing u to the left, all other terms to the right

6u=-48

u=-48/6

u=-8

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