9u+33=4(u-5)

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Solution for 9u+33=4(u-5) equation: 



9u+33=4(u-5)

We move all terms to the left:

9u+33-(4(u-5))=0



We calculate terms in parentheses: -(4(u-5)), so:

4(u-5)

We multiply parentheses

4u-20

Back to the equation:

-(4u-20)



We get rid of parentheses

9u-4u+20+33=0

We add all the numbers together, and all the variables

5u+53=0

We move all terms containing u to the left, all other terms to the right

5u=-53

u=-53/5

u=-10+3/5

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