9u+3=6(u-2)

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Solution for 9u+3=6(u-2) equation: 



9u+3=6(u-2)

We move all terms to the left:

9u+3-(6(u-2))=0



We calculate terms in parentheses: -(6(u-2)), so:

6(u-2)

We multiply parentheses

6u-12

Back to the equation:

-(6u-12)



We get rid of parentheses

9u-6u+12+3=0

We add all the numbers together, and all the variables

3u+15=0

We move all terms containing u to the left, all other terms to the right

3u=-15

u=-15/3

u=-5

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