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9u^2-53u-6=0
a = 9; b = -53; c = -6;
Δ = b2-4ac
Δ = -532-4·9·(-6)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-55}{2*9}=\frac{-2}{18} =-1/9 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+55}{2*9}=\frac{108}{18} =6 $
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