9v+1-3(-2v-2)=5(v-1)

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Solution for 9v+1-3(-2v-2)=5(v-1) equation: 



9v+1-3(-2v-2)=5(v-1)

We move all terms to the left:

9v+1-3(-2v-2)-(5(v-1))=0

We multiply parentheses

9v+6v-(5(v-1))+6+1=0



We calculate terms in parentheses: -(5(v-1)), so:

5(v-1)

We multiply parentheses

5v-5

Back to the equation:

-(5v-5)



We add all the numbers together, and all the variables

15v-(5v-5)+7=0

We get rid of parentheses

15v-5v+5+7=0

We add all the numbers together, and all the variables

10v+12=0

We move all terms containing v to the left, all other terms to the right

10v=-12

v=-12/10

v=-1+1/5

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