9v+22=4(v+8)

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Solution for 9v+22=4(v+8) equation: 



9v+22=4(v+8)

We move all terms to the left:

9v+22-(4(v+8))=0



We calculate terms in parentheses: -(4(v+8)), so:

4(v+8)

We multiply parentheses

4v+32

Back to the equation:

-(4v+32)



We get rid of parentheses

9v-4v-32+22=0

We add all the numbers together, and all the variables

5v-10=0

We move all terms containing v to the left, all other terms to the right

5v=10

v=10/5

v=2

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