9v+32=2(v+2)

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Solution for 9v+32=2(v+2) equation: 



9v+32=2(v+2)

We move all terms to the left:

9v+32-(2(v+2))=0



We calculate terms in parentheses: -(2(v+2)), so:

2(v+2)

We multiply parentheses

2v+4

Back to the equation:

-(2v+4)



We get rid of parentheses

9v-2v-4+32=0

We add all the numbers together, and all the variables

7v+28=0

We move all terms containing v to the left, all other terms to the right

7v=-28

v=-28/7

v=-4

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