9v-7+2(2v+4)=-3(v+1)

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Solution for 9v-7+2(2v+4)=-3(v+1) equation: 



9v-7+2(2v+4)=-3(v+1)

We move all terms to the left:

9v-7+2(2v+4)-(-3(v+1))=0

We multiply parentheses

9v+4v-(-3(v+1))+8-7=0



We calculate terms in parentheses: -(-3(v+1)), so:

-3(v+1)

We multiply parentheses

-3v-3

Back to the equation:

-(-3v-3)



We add all the numbers together, and all the variables

13v-(-3v-3)+1=0

We get rid of parentheses

13v+3v+3+1=0

We add all the numbers together, and all the variables

16v+4=0

We move all terms containing v to the left, all other terms to the right

16v=-4

v=-4/16

v=-1/4

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