9x(-2x-10)=33

Solution for 9x(-2x-10)=33 equation:

9x(-2x-10)=33

We move all terms to the left:

9x(-2x-10)-(33)=0

We multiply parentheses

-18x^2-90x-33=0

a = -18; b = -90; c = -33;
Δ = b2-4ac
Δ = -902-4·(-18)·(-33)
Δ = 5724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5724}=\sqrt{36*159}=\sqrt{36}*\sqrt{159}=6\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-6\sqrt{159}}{2*-18}=\frac{90-6\sqrt{159}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+6\sqrt{159}}{2*-18}=\frac{90+6\sqrt{159}}{-36}
$